0=(x^2-9x+14)/4x

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Solution for 0=(x^2-9x+14)/4x equation: 


x in (-oo:+oo)

0 = x*((x^2-(9*x)+14)/4) // - x*((x^2-(9*x)+14)/4)

0-(x*((x^2-(9*x)+14)/4)) = 0

-(x*((x^2-9*x+14)/4)) = 0

(-1*x*(x^2-9*x+14))/4 = 0

x^2-9*x+14 = 0

x^2-9*x+14 = 0

DELTA = (-9)^2-(1*4*14)

DELTA = 25

DELTA > 0

x = (25^(1/2)+9)/(1*2) or x = (9-25^(1/2))/(1*2)

x = 7 or x = 2

(x-2)*(x-7) = 0

(-1*x*(x-2)*(x-7))/4 = 0

( x-2 )

x-2 = 0 // + 2

x = 2

( x-7 )

x-7 = 0 // + 7

x = 7

( x )

x = 0

x in { 2, 7, 0 }

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